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Assignment 8 - b-Galactosidase Assay
This is mock data for your current project.
Protein was extracted from IPTG induced cells and assayed for total protein.
The extract was poured over a Ni-NTI column and washed with buffer. The 6His-recombinant
protein was eluted with elution buffer and assayed for total protein.
Duplicate samples from the crude extract, the flow-through, the washes and the
eluted 6His-recombinant protein fractions were assayed for the presence of b-galactosidase
activity and compared to a dilution curve generated from pure b-galactosidase.
The results are shown below:
The absorbance at 600 nm for the 1 ml cell culture was 0.2 and the conversion
of absorbance to cells/ml is: 1A600 = 8*10^8
cells/ml. The crude extract was made from 5 ml of cells.
| Sample | Crude extract | Column flow-through | Column wash | Column elution | Standard 1 U/µl |
| protein (mg/ml) | 50 | 49 | 0.24 | 0.4 | 0.2 |
| Total volume (ml) | 10 | 10 | 40 | 1 | 0.001 |
| Absorbance 415 nm | 1/1 dil, 15µl 1.5, 1.5 | 1/1 dil, 15µl 0.108, 0.110 | 1/1 dil, 15µl 0.084, 0.085 | 1/1 dil, 15µl 1.5, 1.5 | no enzyme .078, .077 |
| 1/2 dil, 15µl 1.5, 1.5 | 1/2 dil, 15µl 1.5, 1.5 | 1/1 dilution, 1 unit 0.90, 0.896 |
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| 1/4 dil, 15µl 1.5, 1.5 | 1/4 dil, 15µl 1.5, 1.5 | 1/2 dilution, 0.5 units 0.512, 0.504 |
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| 1/8 dil, 15µl 0.177, 0.175 | 1/8 dil, 15µl 0.886, 0.890 | 1/4 dilution, 0.288, 0.294 |
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| 1/8 dilution, 0.193, 0.192 |
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| 1/16 dilution, 0.137, 0.137 |
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| 1/32 dilution, 0.109, 0.110 |
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| 1/64 dilution, 0.097, 0.097 |
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| 1/128 dilution, 0.090, 0.090 |
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| 1/256 dilution, 0.087, 0.084 |
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| 1/512 dilution, 0.079, 0.080 |
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| 1/1024 dilution, 0.078, 0.077 |
Note that 15 µl of crude or column extract was used in these assays.
One unit of purified enzyme was used in the 1/1 dilution for the standard curve.
The background is the assay with no enzyme.
Calculate the enzyme units for each dilution in the standard curve. Subtract
the background average from each of the average A415
values to get the response due to the enzyme. Plot the standard curve with the
enzyme units on the X-axis and the enzyme response absorbance at 415 nm on the
Y-axis. From the curve, or appropriate regression, estimate how many units of
enzyme are found in the crude and column samples. Calculate how many total units
are contained in each of these samples. Calculate how many total mgs of protein
are contained in each sample. The specific activity of an enzyme is defined
as the number of units of enzyme present per mg of protein. It is an indicator
of the purity of the enzyme and the higher the value the more pure the enzyme.
Calculate the specific activity of the crude and column samples by dividing
the total number of units in each sample by the total mgs of protein in each
sample.
Show the results in a table:
| Sample | Total Protein (mg) | Total Units | Specific Activity (U/mg) |
| Crude Extract | |||
| Column Flow-through | |||
| Column Wash | |||
| Column Eluate |
What is the % yield of your protein purification (total units of purified enzyme / total units in crude extract x 100)?
How much have you been able to purify the enzyme taken from the crude extract
(fold purification = SA of purified enzyme / SA of crude extract)?
On the average, how many units of enzyme are found in each E. coli cell?
Is the specific activity of the column eluate the same as the specific activity
of the purified b-galactosidase used in generation of the standard curve? If
not, then offer an explanation of why it is not the same (don't blame assay
error since the replication error is very low).
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